?- scanl(plus, [1,2,3,4,5], 0, Sums).
Sums = [0, 1, 3, 6, 10, 15].
When considering the lists columns of a table, scanl/5 combines the accumulator with each row to produce the next value in the result list. We illustrate this using plus/4 which adds the accumulator with the values from the row to produce the next accumulator. We use trace/2 to illustrate how the values are combined.
plus(A,B,C,Result) :-
Result is A+B+C.
?- trace(plus/4, exit).
% plus/4: [exit]
?- scanl(plus, [1,2,3,4,5], [10,20,30,40,50], 0, Sums).
T Exit: plus(1, 10, 0, 11)
T Exit: plus(2, 20, 11, 33)
T Exit: plus(3, 30, 33, 66)
T Exit: plus(4, 40, 66, 110)
T Exit: plus(5, 50, 110, 165)
Sums = [0, 11, 33, 66, 110, 165].