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CQL Simple INNER JOIN |
{[], se_lt_x :: [a-J1, c-C] =*= se_lt_y :: [d-J1, f-F]}
The join is se_lt_x.a = se_lt_y.d
because of the shared
variable J1.
se_lt_x.c
will be returned in C and se_lt_y.f
will be returned in
F